Answer Posted / vadivel t

Hi Jhothi16,
how do u say calloc is for reallocation???..

Ans is,

Both are serving for the purpose of dynamic memory
allocation.
But malloc and calloc differs in two ways.

1.After allocating memory using malloc(), the data elements
in the memory will not be initialised. Means, it contains
garbage values.

But calloc() initialise all the data elements to 0.


2.malloc() allocates memory in terms of bytes.it accepts
only one argument, which says no of bytes to be allocated.

But calloc() allocates memory interms of blocks. it is
widely used when there is a need to allocated memory for an
array.

it accepts two arguments, 1st says, no of blocks to be
allocated and next argument says the size of the block.

ex:

calloc(10, sizeof(int))

-> it allocates 40 bytes, if the compiler allocates 4 bytes
for an int variable.

You have given 2 array. You need to find whether they will create the same BST or not. For example: Array1:10 5 20 15 30 Array2:10 20 15 30 5 Result: True Array1:10 5 20 15 30 Array2:10 15 20 30 5 Result: False One Approach is Pretty Clear by creating BST O(nlogn) then checking two tree for identical O(N) overall O(nlogn) ..we need there exist O(N) Time & O(1) Space also without extra space .Algorithm ?? DevoCoder guest Posted 3 months ago # #define true 1 #define false 0 int check(int a1[],int a2[],int n1,int n2) { int i; //n1 size of array a1[] and n2 size of a2[] if(n1!=n2) return false; //n1 and n2 must be same for(i=0;ia1[i+1]) && (a2[i]>a2[i+1]) ) ) return false; } return true;//assumed that each array doesn't contain duplicate elements in themshelves }

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