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Answer Posted / raghavan
Every process has a address boundary. When a process does a malloc, memory is allocated from this boundary location and the process address boundary is moved to the new end. In linux, there is a function sbrk() that allows to change the process address boundary. sbrk(0) will return the current process address boundary and sbrk(n) will move the process boundary by n bytes.
malloc internally uses this feature to allocate memory for the requesting process.
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