d) it will print 0.0000. If we typecast the result to float as shown be

main()

{

int i, j, *p;

i = 25;

j = 100;

p = &i; // Address of i is assigned to pointer p

printf("%f", i/(*p) ); // i is divided by pointer p

}

a. Runtime error.

b. 1.00000

c. Compile error

d. 0.00000

Question Posted / rk

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Answer Posted / rk

d) it will print 0.0000.

If we typecast the result to float as shown below then
expected output will be printed(i.e. 1.0000)
printf("%f",(float) i/(*p) ); // i is divided by pointer p

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