Answer Posted / amit singh

when you put String s = new String(null)
you will get the thing waht i'm trying to say that
beacuse my english is weak so what i'm trying to say
understatd
beacuse there is no realtion between the
1)which is for literal
2)which is for new String()
don't add both at the same time
because both are different question itself and different
answer itself.
but you will connect that then the problem is your own so
please
if you try to add both the thing is comeup
throug the itself that the hello string in a pool for the
first statement
so for the second String s = new String("hello");
compiler go to the pool and and check that "hello" it is
present if it present then it will pick it through the pool
and assign it to the overloaaded constructor of the String
class which will take the String(string s)so new operator
creates new object which will contain the hello.
and the the new String object will create so please check
to put String s = new String(null)
you will get ambiguous error
overloaded constructor in String class
String(String s) and String(StringBuffer s) and many
and you will get what i'm trying to say so do't add
ist STATEMENT TO SECOND WHICH IS FOR NEW STRING()
thanks
amitsing2008@gmail.com

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