Answer Posted / pradeep

Dear frd,

char a[20];
a="Hello Orcale Test";

Here you are trying to "assign" constant char string to
address variable , as you are aware that name of an array
points to the first address of the array element. So here
you wil get an error message saying L value is required.

and also
char *a;
*a="hello" ; also will give an error as you are trying to
assign constant characters to char type variable.
Type mismatch will occur.

so I suggest you to use the strcpy method to copy a
constant character string to char*

so soln is
char a[20];
strcpy(a,"hello world");

or char *a;
a="hello";

Define Array of pointers.

635

---

What are keywords in c with examples?

604

---

What is meant by preprocessor in c?

536

---

Explain bitwise shift operators?

632

---

Is null always defined as 0(zero)?

616

---

---

Place the #include statement must be written in the program?

573

---

Explain how can I convert a number to a string?

650

---

Explain what does the function toupper() do?

636

---

Why does the call char scanf work?

620

---

Explain how can a program be made to print the name of a source file where an error occurs?

691

---

4-Take two sets of 5 numbers from user in two arrays. Sort array 1 in ascending and array 2 in descending order. Perform sorting by passing array to a function mySort(array, sortingOrder). Then multiply both the arrays returned from function, using metric multiplication technique in main. Print result in metric format.

1727

---

A program is required to print your biographic information including: Names, gender, student Number, Cell Number, line of study and your residential address.

1253

---

Difference between strcpy() and memcpy() function?

680

---

Is exit(status) truly equivalent to returning the same status from main?

587

---

Explain what is meant by high-order and low-order bytes?

635

---