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a watch which looses uniformly was observed to be 12 min
fat at 4am.on 6th of a month.it showed 20 min less than
thae correct time at 6pm on the 10th of the same month.when
did the watch show correct time
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Answer Posted / alphy
ans: 8:10 pm on 7th of the month
12min fast at 4 am on 6th
20min slow (less)at 6pm on 10th
i.e-> 32 mins changed in 110 hrs ( from 6th to 10th )
we have to find d time passed where change is 12 min .. dat
nullifies the 12 min fast effect ...
32 -> 110 hrs
12 -> 40hrs and 10 mins
4:00 am + 40 hrs + 10 mins -> 8:10 pm on 7th of the month
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