Write an interactive c program that will encode or decode a
line of text. To encode a line of text, proceed as follows:
Convert each character, including blank spaces, to its
ASCII equivalent.
Generate a positive random integer. Add this integer to the
ASCII equivalent of each character. The same random integer
will be used for the entire line of text.
Suppose that N1 represents the lowest permissible value in
the ASCII code, and N2 represents the highest permissible
value. If the number obtained in step 2 above exceeds N2,
then subtract the largest possible multiple of N2 from this
number, and add the remainder to N1. Hence the encoded
number will always fall between N1 and N2, and will
therefore always represent some ASCII character.
Display the characters that correspond to the encoded ASCII
values.
The procedure is reversed when decoding a line of text. Be
certain, however, that the same random number is used in
decoding as was used in encoding.
Answer Posted / sss
#include<iostream.h>
#include<string.h>
void main()
{
char str1[]="Testing";
char str2[40];
strcpy(str2, str1);
cout<<"str1="<<str1<<endl;
cout<<"str2="<<str2<<endl;
int i=0;
while(str1[i]!='\0')
{
cout<<(int)str1[i]<<" ";
str2[i]=(char)((int)str1[i]+2);
i++;
}
cout<<endl;
i=0;
while(str2[i]!='\0')
{
cout<<(int)str2[i]<<" ";
i++;
}
cout<<endl;
cout<<str2<<endl;
i=0;
while(str2[i]!='\0')
{
cout<<(char)((int)str2[i]-2);
i++;
}
cout<<endl;
}
| Is This Answer Correct ? | 14 Yes | 32 No |
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You have given 2 array. You need to find whether they will
create the same BST or not.
For example:
Array1:10 5 20 15 30
Array2:10 20 15 30 5
Result: True
Array1:10 5 20 15 30
Array2:10 15 20 30 5
Result: False
One Approach is Pretty Clear by creating BST O(nlogn) then
checking two tree for identical O(N) overall O(nlogn) ..we
need there exist O(N) Time & O(1) Space also without extra
space .Algorithm ??
DevoCoder
guest
Posted 3 months ago #
#define true 1
#define false 0
int check(int a1[],int a2[],int n1,int n2)
{
int i;
//n1 size of array a1[] and n2 size of a2[]
if(n1!=n2) return false;
//n1 and n2 must be same
for(i=0;i
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