Answer Posted / nakul sharma
Memory allocated for any structure is equal to the sum of
memory required by each structure member.
Example: In a structure 'abc' below, memory allocated will
be 7 Bytes (2 Bytes for int a + 1 Byte for char b + 4 Bytes
for float c ina 32 bit processor)
struct abc
{
int a;
char b;
float c;
}
But in union memory allocated for it is equal to the memory
required by the biggest (in terms of memory it use) union
member.
Example: In a union 'abc' below, memory allocated will be 4
Bytes as float c is the biggest union member here and it
uses 4 Bytes of memory in 32 bit processor.
union abc
{
int a;
char b;
float c;
}
Is This Answer Correct ? | 19 Yes | 1 No |
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DevoCoder
guest
Posted 3 months ago #
#define true 1
#define false 0
int check(int a1[],int a2[],int n1,int n2)
{
int i;
//n1 size of array a1[] and n2 size of a2[]
if(n1!=n2) return false;
//n1 and n2 must be same
for(i=0;i