Answer Posted / nikhil patil

#include<stdio.h>
#include<conio.h>main()
{
int a[5],even=0,odd=1,i;

for(i=0;i<5;i++)

scanf("%d",&a[i]);
/* display the number of odd and even intergers */
for(i=0;i<5;i++)
{
if((a[i]%2 ==0))
even++;
if((a[i]%2==1))
odd++;
}
printf("%d",even,);
printf ("%d",odd,);
getch();

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