Requirement is:
try
{
\\SQL Query
}
catch(Exception i)
{
print a
}
catch(SQLQueryException e)
{
\\SQL Query
}
Qu)I Got Exception in "try" block. Which "catch" statement
(i.e. 1st catch or 2nd catch ) catches the exception and
Why???
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Answer Posted / sathish
There will be compile time error, becuase
the "..........catch(Exception ex)..........." is generic
exception block, where all type of exceptions are caught,
so when "catch(Exception ex)" is placed in the beginning,
then the following compile time error is thrown.
"A previous catch clause already catches all exceptions of
this or of a super type ('System.Exception')"
| Is This Answer Correct ? | 10 Yes | 1 No |
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