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main()
{
char *p="GOOD";
char a[ ]="GOOD";
printf("\n sizeof(p) = %d, sizeof(*p) = %d, strlen(p) = %d",
sizeof(p), sizeof(*p), strlen(p));
printf("\n sizeof(a) = %d, strlen(a) = %d",
sizeof(a), strlen(a));
}
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Answer Posted / susie
Answer :
sizeof(p) = 2, sizeof(*p) = 1, strlen(p) = 4
sizeof(a) = 5, strlen(a) = 4
Explanation:
sizeof(p) => sizeof(char*) => 2
sizeof(*p) => sizeof(char) => 1
Similarly,
sizeof(a) => size of the character array => 5
When sizeof operator is applied to an array it returns the
sizeof the array and it is not the same as the sizeof the
pointer variable. Here the sizeof(a) where a is the
character array and the size of the array is 5 because the
space necessary for the terminating NULL character should
also be taken into account.
| Is This Answer Correct ? | 1 Yes | 1 No |
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