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void main()
{
while(1){
if(printf("%d",printf("%d")))
break;
else
continue;
}
}
- 1 Answers
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Answer Posted / susie
Answer :
Garbage values
Explanation:
The inner printf executes first to print some garbage value.
The printf returns no of characters printed and this value
also cannot be predicted. Still the outer printf prints
something and so returns a non-zero value. So it encounters
the break statement and comes out of the while statement.
| Is This Answer Correct ? | 21 Yes | 3 No |
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