struct point
{
int x;
int y;
};
struct point origin,*pp;
main()
{
pp=&origin;
printf("origin is(%d%d)\n",(*pp).x,(*pp).y);
printf("origin is (%d%d)\n",pp->x,pp->y);
}
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Answer Posted / susie
Answer :
origin is(0,0)
origin is(0,0)
Explanation:
pp is a pointer to structure. we can access the elements of
the structure either with arrow mark or with indirection
operator.
Note:
Since structure point is globally declared x & y are
initialized as zeroes
| Is This Answer Correct ? | 4 Yes | 0 No |
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