main()
{
int i=-1;
-i;
printf("i = %d, -i = %d \n",i,-i);
}
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Answer Posted / susie
Answer :
i = -1, -i = 1
Explanation:
-i is executed and this execution doesn't affect the value
of i. In printf first you just print the value of i. After
that the value of the expression -i = -(-1) is printed.
| Is This Answer Correct ? | 6 Yes | 1 No |
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