c) Error becoz i/(*p) is 25/25 i.e 1 which is int & printed as a float

main()

{

int i, j, *p;

i = 25;

j = 100;

p = &i; // Address of i is assigned to pointer p

printf("%f", i/(*p) ); // i is divided by pointer p

}

a. Runtime error.

b. 1.00000

c. Compile error

d. 0.00000

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Answer Posted / guest

c) Error becoz i/(*p) is 25/25 i.e 1 which is int & printed
as a float,

So abnormal program termination,

runs if (float) i/(*p) -----> Type Casting

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