Answer Posted / gunasekaran

rated KV*percentage impedance we can get impedance voltage.
then applied voltage*rated current/rated impedance voltage
for example
) Power transformer, 33/11KV, 5MVA, 87. 5A/262.5A
Z = 6.81% at principal tap, mains voltage : 372V
6.81% of 33KV = (33000 x 6.81/100) = 2247.3V
2247.3V will deliver rated current of 87.5A on
short circuit.
372V will deliver a short circuit current of (372 x
87.5 / 2247.3) = 14.48A
At principal tap, short circuit current on HV side
= 14.48A.
Short circuit current on LV side = (14.48 x
33/11) = 43.45A

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