Answer Posted / p balaji
The energy consumed is given by
e=p*t
power(p)=v*i*powerfactor
active power=v*i*cos(phasediff)
reactive power=v*i*sin(phase diff)
Apparent power=sqrt(p square+q square)
t:time in hours
p in kilowatts
1kwh=1 unit
| Is This Answer Correct ? | 0 Yes | 5 No |
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