what is the subnet for the host ip address 172.16.210.0/22
Answer Posted / venkatesh i patil
no of subnet bits=6
no of subnets=2power6=64
no of host bits=10
no of valid hosts=(2power10)-2
increment=2power(no of host bits in interested octet)[here
interested octet is 3rd octet]=2power2=4
the multiple of 4 nearer to 210 is 208 so the subnet starts
with 172.16.208.0
subnet first valid host last valid host broadcast id
..16.208.0 172.16.209.0 172.16.210.0 172.16.211.0
172.16.208.0 is currect...
Is This Answer Correct ? | 7 Yes | 4 No |
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