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what is the subnet for the host ip address 172.16.210.0/22
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Answer Posted / venkatesh i patil
no of subnet bits=6
no of subnets=2power6=64
no of host bits=10
no of valid hosts=(2power10)-2
increment=2power(no of host bits in interested octet)[here
interested octet is 3rd octet]=2power2=4
the multiple of 4 nearer to 210 is 208 so the subnet starts
with 172.16.208.0
subnet first valid host last valid host broadcast id
..16.208.0 172.16.209.0 172.16.210.0 172.16.211.0
172.16.208.0 is currect...
| Is This Answer Correct ? | 7 Yes | 4 No |
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