18) d o/p is 2 5 19) d o/p is 100 200 100 20) none Answer is 1,2

18)struct base {int a,b;
base();
int virtual function1();
}
struct derv1:base{
int b,c,d;
derv1()
int virtual function1();
}
struct derv2 : base
{int a,e;
}
base::base()
{
a=2;b=3;
}
derv1::derv1(){
b=5;
c=10;d=11;}
base::function1()
{return(100);
}
derv1::function1()
{
return(200);
}
main()
base ba;
derv1 d1,d2;
printf("%d %d",d1.a,d1.b)
o/p is
a)a=2;b=3;
b)a=3; b=2;
c)a=5; b=10;
d)none
19) for the above program answer the following q's
main()
base da;
derv1 d1;
derv2 d2;
printf("%d %d %d",da.function1(),d1.function1(),d2.function1
());
o/p is
a)100,200,200;
b)200,100,200;
c)200,200,100;
d)none
20)struct {
int x;
int y;
}abc;
you can not access x by the following
1)abc-->x;
2)abc[0]-->x;
abc.x;
(abc)-->x;
a)1,2,3
b)2&3
c)1&2
d)1,3,4

Question Posted / naresh s

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Answer Posted / naresh s

18) d
o/p is
2 5
19)
d
o/p is
100 200 100
20) none
Answer is 1,2 & 4.

Is This Answer Correct ?

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