The 4/5th part of volume of a piece of wood is swiming as
well as sunk in a fluid. if the relative dencity of wood is
0.8 then what will be the dencity of fluid in KG/M3.
PLEASE ANSWER WITH SOLUTION.
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Answer Posted / mechatronics89
let p1 = density of wood and p2 be dat of fluid.
applying force balance
p1*V*g= p2*(4/5)V*g (gravity = buoyant force)
800=.2*p2
p2=4000 kg/m^3
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