Answer Posted / pradeep

In Linux, its 12 bytes.
int a ------- 4 bytes
char b ------- 1 byte.
but as the next element is integer, it wont fit in the
remaining 3 bytes left after the "char b" occupies the first byte of the 4 byte chunk. so these 3 bytes wont be used for storing "int *p". these will be padded. next 4 bytes will be used for storing *p.

to prove it.

int size;
size = (&(abc.p) + sizeof(abc.p)) - &abc.a ;
printf("size = %d",size);

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