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for(i=1;i>0;i++);
printf("i=%d",i);
what will be the answer????
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Answer Posted / vignesh1988i
since after the loop there is a semicolon , so according to
the compiler this semicolon will be taken as next line and
the loop will be iterating till the termination condition....
output possibilities :
1)if the variable 'i' which is used as an signed integer
variable , this will take an infinite values and stop at one
instance and it will terminate the application. but wont
display anything in the screen
2) if this is an unsigned variable this will be infinite
with values going on and on without stopping.. but not
displaying it...
conclusion : loop is infinite here.....
thank u
| Is This Answer Correct ? | 12 Yes | 8 No |
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