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Answer Posted / naga
Consider two objects, A and B, which each refer to two
memory blocks xi and yi (i = 1, 2,...). Think of A and B as
strings and of xi and yi (i = 1, 2,...) as the characters
they contain.
Shallow copy
One of them is the shallow copy. In this process B is
attached to the same memory block as A. This is otherwise
known as address copy
Deep copy
An alternative is a deep copy. Here the data is actually
copied over.
Example:
class base
{
public:
int i;
base()
{
i=0;
}
base(int j)
{
i=j;
}
};
main()
{
using namespace std;
base *p1=new base(23);
base *p2;
//Shallow copy, here we are using pointers and we are
copying content of one pointer to another.so address will
get copied.
p2=p1; // address is copied
cout<<"\naddress of P1:"<<p1;
cout<<"\nvalue at p1:"<<p1->i;
cout<<"\naddress of P2:"<<p2;
cout<<"\nvalue at p2:"<<p2->i;
delete p2;
cout<<"\naddress of P1 after delete:"<<p1;
cout<<"\nvalue in P2 after delete:"<<p2->i;
//DEEP copy, here we are creating objects and we are
copying content of one object to another.So content will
get copied.
base o1(67);
base o2;
o2=o1;//contents are copied. But, the addresses
remained different
cout<<"\nvalue in o1:"<<o1.i;
cout<<"\nvalue in o2 after copy:"<<o2.i<<endl;
return 0;
}
output:
address of P1:0x00323C88
value at p1:23
address of P2:0x00323C88
value at p2:23
address of P1 after delete:0x00323C88
value in P2 after delete:-572662307
value in o1:67
value in o2 after copy:67
| Is This Answer Correct ? | 18 Yes | 1 No |
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