int *p=20; means int *p; p=20; so the address of p is 20 printf("

int *p=20;
if u print like dis printf("%d",p);
o\p:- 20; how is it possible?
plz give me the explanation.

Question Posted / valli

15 Answers
24953 Views
Global Edge, I also Faced
E-Mail Answers

Answer Posted / valli

int *p=20;
means
int *p;
p=20;
so the address of p is 20
printf("%d",p);
it prints 20 because now the base address of p is 20
even if we print as
printf("%u",p);
the o/p will be 20

Is This Answer Correct ?

9 Yes

2 No

Post New Answer View All Answers

Please Help Members By Posting Answers For Below Questions

what is the syallabus of computer science students in group- 1?

2325

what is the function of pragma directive in c?

1127

List some of the static data structures in C?

1204

What are different storage class specifiers in c?

1097

I have a varargs function which accepts a float parameter?

1058

What is difference between far and near pointers?

1049

Explain how can I avoid the abort, retry, fail messages?

1061

Is it possible to execute code even after the program exits the main() function?

1350

in linking some of os executables are linking name some of them

2144

What is difference between array and pointer in c?

1100

What is difference between structure and union in c programming?

1118

Why is a semicolon (;) put at the end of every program statement?

1077

Difference between strcpy() and memcpy() function?

1158

please give me a VIRTUSA sample palcement papers.... you will only send TECHNICAL SECTION..... that is help for me Advance Thanks........................

2036

Not all reserved words are written in lowercase. TRUE or FALSE?

1237