Answer Posted / arpit dhandhania

Answer #2: You have assigned the elements of the array in
the program itself which by default starts from array index
0 that is the numbers goes into the array indices 0 1 2 3
4 and you have not initialzed or modified the value of i in
the first loop which happens to be a garbage or 0 so the
count goes to infinite. coz a[i] is never '\0'
Secondly in a numeric array last element in not null
character it is only in case of character arrays.
Assuming that you have implemented the 1st loop correctly
and you have the length of array a in count ie = 4 since u
are starting from 0 then you have initialized i to count
which makes i = 4.In the second loop the condition is i>=1
so i=0 is never visited and thus a[0] ir not displayed
(remember in C array starts from 0 by default).

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