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There are 9 balls of equal size and same weight(they look
similar) except 1. How many weights required to find the
dissimilar ball using a weighing balance?
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Answer Posted / mopurizwarriors
anwer is zero!!
here is the explanation:
first divide the balls into almost two equal groups!
i.e.,5 and 5 balls in 2 groups.
then compare the weights of two groups:
again,divide the first and second groups into almost equal
groups!!(say them as 1,2,3,4 groups,where 1,2 are from first
group and 3,4 are from second group).
let group-1 contains 3 balls and group-2 contain 2 balls
find weights of group-1 and group-2.say x,y
so,average weight of balls in group-2 is x/3.
if 2*(x/3)=y,then that odd ball is not present in first
group(don't confuse group-1 with first group).
so,that odd ball may be present in either group-3 or group-4.
continue,the process until u get groups containing only one
ball.
IN THIS METHOD ,YOU HAVEN'T USED ANY WEIGHTS!!!
SO,THE ANSWER IS:zero
| Is This Answer Correct ? | 4 Yes | 17 No |
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