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Answer Posted / aditya raj
// magic square for odd numbers....
#include<stdio.h>
main()
{
int n;
scanf("%d",&n);
int a[n][n],i,j;
int row[n],col[n],dia[2]={0};
for(i=0;i<n;i++)
{
row[i]=0;
col[i]=0;
}
int num=1;
int nn=n*3/2;
for(i=0; i < n; i++)
for(j=0; j < n; j++)
a[(j-i+nn)%n][(i*2-j+n)%n]=num++;
for(i=0; i < n; i++)
{ for(j=0; j < n; j++)
{
printf("%d ",a[i][j]);
}
printf("\n");
}
}
| Is This Answer Correct ? | 0 Yes | 1 No |
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