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Answer Posted / pankaj kumar sharma
Function overloading takes place when a function is
overloaded with two or more tasks ie. same function is
having different behaviour.
It takes place when two functions have same name but
differs in argument list ie. may be the no of arg in both
fun are different or type of the arguments in argument list
are diff.
As return type of a func. does not take part in name
mangling so return type for overloaded functions may differ
or not.
eg: int fun(int arg1, int arg2)
char* fun(char* ptr1)
| Is This Answer Correct ? | 8 Yes | 2 No |
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