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2 vessels A and B contain spirit and water in the ratio of
5:2 and 7:6 respectively .find the ratio in which these
mixtures be mixed 2 obtain a new mixture in the vessel
containg spirit and water in the ratio 8:5
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Answer Posted / gautam nath
Step (i) : Let C.P. of spirit be Re.1
Given ratio of mixture in A = 5:2
spirit in 1 lit mixture in A = 5/7 lit
C.P of 1 lit mixture in A = Rs. 5/7
Ratio of Mixture in B = 7:6
spirit in 1 litre mixture in B – 7/13 lit
C.P of 1 lit mixture in B = Rs. 7/13
Ratio of new mixture = 8:5
spirit in 1 lit mixture = 8/13
C.P of 1 lit mixture = Rs. 8/13 (Mean price)
Step (ii) : By the rule of allegation,
i. C.P of 1 liter of mixture in A =5/7
ii. C.P of 1 liter of mixture in B = 7/13
iii. Mean price (p) = 8/13
iv. d – m = 5/7 – 8/13 = 9/91
v. m – c = 8/13 – 7/13 = 1/13
Required ratio = 2/91 : 1/13 = 9:7
| Is This Answer Correct ? | 19 Yes | 3 No |
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