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What does the following command line produce? Explain each
aspect of this line.
$ (date ; ps -ef | awk {print $1}' | sort | uniq | wc -l )
>> Activity.log
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Answer Posted / vijay
There is a syntactical error in the question
The Actual command should be like
$(date;ps -ef | awk '{print $1}' | sort | uniq | wc -l ) >>
Activity.log
Answer::
"date" command gives the date
"ps -ef" -- gives all the process informations
awk '{print $1}'--- cuts the first column in the processes
(which is the usernames)
sort-- sorts all the usernames
uniq-- gives unique usernames
"wc -l" -- gives the total number of users running process
In compact--- The command displays the date and the number
of users(not repeated) who are executing some process.
The result when Activitylog is viwed after the execution
should be like
>>Fri Apr 3 12:48:21 IST 2009
>>38
| Is This Answer Correct ? | 16 Yes | 0 No |
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