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#include <stdio.h>
#define sqr(x) (x*x)
int main()
{
int x=2;
printf("value of x=%d",sqr(x+1));
}
What is the value of x?
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Answer Posted / pravin
sqrt(x+1)(x+1*x+1)
as x=2;result will be 2+1*2+1=5;
thank u
| Is This Answer Correct ? | 6 Yes | 1 No |
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