void swap(int a,int b)
{
a=a+b;
b=a-b;
a=a-b;
}
in this code always gives the same result for all case
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Answer Posted / moorthy
here a and b are local variable in function swap() where a
and b are swapped inside swap().so that swaping does not
affect variable in main().
| Is This Answer Correct ? | 12 Yes | 1 No |
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