why there are multiple catches for a try block.don't tell me
that there can be multiple exception of a code segment
that's why.tell me the real fact behind this.
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Answer Posted / tulasi prasad
I under stood ur problem, I will expalin with an example
public class Test
{
public static void main(String args[])
{
try
{
int n =2/args.length;
int x[]={1,2};
x[30]=4;
}
catch(ArithmeticException e)
{
System.out.println("Divede by Zero");
}
catch(IndexOutOfBoundsException e)
{
System.out.println("ArrayIndex Out of
Bounds");
}
}
}
if u run with out any commandline argument then u got
divide by zero exception. otherwise u get indexbounds
exception
| Is This Answer Correct ? | 2 Yes | 0 No |
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