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void main()
{int a[5],i,b=16;
for(i=0;i<5;i++)
a[i]=2*i;
f(a,5,b);
for(i=0;i<5;i++)
printf("\n %d",a[i]);
printf("\n %d",b);
}
f(int *x,int n,int y)
{
int i;
for(i=0;i<n;i++)
*(x+i)+=2;
y=y+2;
}wat r the errors in the prg.and improvise the prg to get o/p.?
- 2 Answers
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Answer Posted / vignesh1988i
so , i can understand at first you are inputting
implicitally the values in the array using the variable
used in for loops... then you are changing the values again
by writing the function... sending the base address of the
array.. then only once the y value will get added by 2...
as for as me their is no error in your program... so ur o/p
will be :
2
4
6
8
10
16
BUT IN ORDER TO MAKE OUT THE VALUE OF 'Y' TO BE
INCREMENTED FOR EACH VALUE IN THE LOOP AND TRY TO MAKE
CHANGE DIRECTLY IN THE ADDRESS , make these corrections
f(a,5,&b); , f(int *x,int n,int *y) , the for loop may be
like this :
for(i=0;i<n;i++)
{
(*(x+i))=(*(x+i))+2;
(*y)=(*y)+2;
}
after this ur o/p will be :
2
4
6
8
10
26
thank u
| Is This Answer Correct ? | 1 Yes | 0 No |
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