String is an immutable object.
Then how can the following code be justified.
String s1 = ?ABC?;
String s1 = s1+?XYZ?;
s.o.p(s1);
The output is ABCXYZ, which is the value of s1 ?
Answer Posted / k.shiva
here we define s1="ABC".That means one new string is
created.And this string value is stored in heap its
refrence variable is s1.when we say s1+"XYZ".Then string s1
i.e ABC and XYZ are concadinated by using concadination
operater.It forms a new string i.e "ABCXYZ" in heap.But
again we assign this value to the refrence variable
s1.Then "ABCXYZ" value is assign to s1 and the string "ABC"
which is garbage collected.
| Is This Answer Correct ? | 12 Yes | 4 No |
Post New Answer View All Answers
What is a ternary operator in java? What is an interface?
How hashmap works in java?
What do you mean by exception handling in Java?
What is executor memory?
Differentiate between class and structure.
What is the disadvantage of synchronization?
What is anonymous inner class?
Explain about features of local inner class?
What is the difference between Java1.4 and Java1.5
How does hashset work in java?
Is null a value?
What is the difference between a vector & an array list?
Why isn’t there operator overloading?
What super () does in java?
what is the purpose of the runtime class?