Answer Posted / vijayakumar chinnasamy

Method overrrideing is the runtime polymorphism.The
class's "object" only determine which method to called .
eg:
class SuperClassTest
{
public void display(){
System.out.println("Super class");
}
}
class SubClassTest extends SuperClassTest
{
public void display(){
System.out.println("Sub class");
}
}
public class TestPro {



public static void main(String[] args) {

SuperClassTest sub=new SubClassTest();
System.out.print("I am Calling
subclasstest's display() method: ");
sub.display();

SuperClassTest sup=new SuperClassTest();
System.out.print("I am Calling
superclasstest's display() method: ");
sup.display();
}

}


o/p:

I am Calling subclasstest's display() method: Sub class
Note: object is type of SubClassTest
I am Calling superclasstest's display() method: Super class
Note: object is type of SuperClassTest

Note:
Method overloading is compile time polymorphism.The
class "reference" type determine which method to be called.

What are accessor methods in java?

1011

---

What is a platform?

1078

---

Difference between keyword and identifier.

1034

---

What is use of a abstract variable?

990

---

When is the finalize() called? What is the purpose of finalization?

1080

---

Name and explain the types of ways which are used to pass arguments in any function in java.

1079

---

What is byte code and why is it important to java’s use for internet programming?

1132

---

What are generic methods?

977

---

What is difference between this and super keyword?

988

---

Is set thread safe java?

926

---

How to overcome the exception object reference not set to an instance of object?

1153

---

What is considered an anti pattern?

932

---

What are the types of java?

1106

---

Name few java util classes introduced with java 8 ?

917

---

what happens when a thread cannot acquire a lock on an object? : Java thread

1049

---