what is the output of the following program?
#include<stdio.h>
void main()
{
float x=1.1;
while(x==1.1)
{
printf("\n%f",x);
x=x-0.1;
}
}
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Answer Posted / vikram
No output.Since a float variable is compared with double
constant,condition will not satisfy.
if you don't believe,try your hand on it.
| Is This Answer Correct ? | 31 Yes | 3 No |
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