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What will be the result of the following program?
main()
{
char p[]="String";
int x=0;
if(p=="String")
{
printf("Pass 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
else
{
printf("Fail 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
}
a) Pass 1, Pass 2
b) Fail 1, Fail 2
c) Pass 1, Fail 2
d) Fail 1, Pass 2
e) syntax error during compilation
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Answer Posted / vikram
b)fail1,fail2
bcoz whenever we compare strings,we use strcmp()
function,hence the condition in if() will not be true,
the control will go into else part and will print fail1,then
size of array p is 6 and sizeof(p)-2 results to 4 and hence
p[4]=='n'which again makes the condition in the if()
false,hence fail2 in else part will be printed.
thnx
| Is This Answer Correct ? | 1 Yes | 1 No |
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