A starts from a place at 11.00 am and travels at a speed of
4 kmph , B starts at 1.00 pm and travels with speeds of 1
kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the
next hr and so on. At wht time will B catch up with A ?
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Answer Posted / jhilam bera
At 1:00 pm the dif'n between A & B = 8 km
after 2:00 pm ................... = 11 km (as B's speed
is 1 and A's 4km, then eqv speed=(4-1)=3km)
After 3:00....................... = 13km (as B's speed 2km)
After 4:00....................... = 14km
after 5:00....................... = 14km (A's speed= B's
speed)
after 6:00....................... = 13km
after 7:00....................... = 11km
after 8:00....................... = 8km
after 9:00....................... = 4km
and now the eqv speed is= (9-4) =5km/hr;
and the remaning distance is 4km;
then, time=(60*4)/5=48 min;
then the meeting time is=9:00+48min=9:48 pm;
| Is This Answer Correct ? | 44 Yes | 5 No |
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