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Suppose there are two cylinders / vessels.In one cylinder
the pressure is 1.5 bar & in other 0.5 bar.If both cylinder
are connected internally through valve connection, what
will be the final pressure in both?
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Answer Posted / sunil
pressure changes still they come to thermal eqilibrium .
final volume=v1+v2 use p*v=n*R*t=====>T=PV/NR
FINAL TEMPERATURE T=P(V1+V2)/NR
P(V1+V2)/NR= (P1V1+P2V2)/NR
FINAL PRESSURE=(P1V1+P2V2)/(V1+V2)
SO TO CONCLUDE EITHER VOLUME OR TEMPERATURE OF
VESSELES MUST BE GIVEN.
IF VOLUME OF BOTH THE VESSELS IS SAME
FINAL PRESSURE=(P1+P2)V/2V
====>P=(P1+P2)/2=1bar
| Is This Answer Correct ? | 16 Yes | 6 No |
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Greetings This question is about hydraulics and I request an expert to answer it. A simple hydraulic machine is made up of two heads, a larger one with a larger force inside a wider pipe and a smaller one with a smaller force inside a smaller pipe in width as in the second picture on this link: http://science.howstuffworks.com/hydraulic1.htm The question is this: what happens if the smaller head and the smaller force doesn’t exist but the smaller pipe is high enough to take all the liquid? For example the larger head is 1.00 sqr metre and can go down 1.00m under a weight of 100.00kg. The cross sectional area of the smaller pipe is 0.001 sqr metre. Now when the larger head goes down 1.00m, how high the liquid from the wider pipe can go into the smaller pipe of the cross sectional area of 0.001 sqr metre? Regards
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