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fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d", x);
}
above function is called as:
fun(10);
what will it print?
}
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Answer Posted / shilpa m
Right answer is 0.
fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d\n", x);
}
Here if fun(10)is called the sequence goes as fun(10)->fun
(5)->fun(2.5)->fun(1.25)->fun(0.625) after this itself
printf will be executed and 0 is printed.
please expalin how answer is 0 1 2 5 10 is right answer???
| Is This Answer Correct ? | 1 Yes | 1 No |
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