UINT i,j;
i = j = 0;
i = ( i++ > ++j ) ? i++ : i--;
explain pls....
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Answer Posted / vignesh1988i
UNIT i,j :
this line indicates that UNIT is an user defined data type. it may been declared as follows :
typedf int UNIT
we are making the code more readable
i=j=0 : indicates that the var. i and j are declared as 0
i=(i++>++j) ? i++ : i-- : the process here is
i++ is an post incrementation . if this is compared with any relational or any operaters first that value will be operated first and the 'i' will get incremented ........
but ++j if we take first thing it will increment the value and then operation will be performed
so when it is compared first i will be 0 and j will be 1 so 0 is not greater than 1. so false, so it will go to the statement after ':' so i-- is there so final value of i will be 0.
thank u
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