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write the function. if all the character in string B appear in
string A, return true, otherwise return false.
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Answer Posted / satish nerlekar
//assuming both the strings in same case
int main()
{
string A;
string B;
int count = 0;
char repeatChar='$';
cout<<"Enter string A";
cin>>A;
cout<<"Enter the string B";
cin>>B;
if(A.length()<B.length())
{
cout<<"Length of string A is small than B, so all the charaters of the B can't be there in A";
exit(0);
}
int A_length = A.length();
int B_length = B.length();
for(int i=0; i<B_length; i++)
{
for(int j=0; j<A_length; j++)
{
if(A[j] == B[i])
{
if(repeatChar == A[j])
;
else
{
count++;
repeatChar = A[j];
break;
}
}
}
}
if(count==B_length)
cout<<"string A has all the chars of string B";
else
cout<<"string A doesn't have all chars of string B";
return 0;
}
| Is This Answer Correct ? | 1 Yes | 0 No |
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