1)#include <iostream.h>
int main()
{
int *a, *savea, i;
savea = a = (int *) malloc(4 * sizeof(int));
for (i=0; i<4; i++) *a++ = 10 * i;
for (i=0; i<4; i++) {
printf("%d\n", *savea);
savea += sizeof(int);
}
return 0;
}
2)#include <iostream.h>
int main()
{
int *a, *savea, i;
savea = a = (int *) malloc(4 * sizeof(int));
for (i=0; i<4; i++) *a++ = 10 * i;
for (i=0; i<4; i++) {
printf("%d\n", *savea);
savea ++;
}
return 0;
}
The output of this two programs will be different why?
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Answer Posted / d289
because when incremented by size of int(4), point to invalid
position in the int array. Hence it will print out only one
correct out put for the first element and garbage for the
rest in the first program while for the second program it
will print out the contents of the int array correctly.
| Is This Answer Correct ? | 3 Yes | 0 No |
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