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Move Zeroes to I
move 5 to j
perform para1 varying I from 10 by -2 until I = 0
display j.
para1.
Add 5 to j.
What’ll be the value after execution of display stmt.
A) 35
B) 40
C) 30
D) 25
please explain how?
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Answer Posted / avi
The value of J before the Para call is 5.
Now,the loop executes for 6 times, so 5*6 is added to the
existing value of J.
J=5+(5*6)
=35.
The correct option is 35.
| Is This Answer Correct ? | 7 Yes | 12 No |
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