Answer Posted / stephen

#include <iostream>
#include <string>
using namespace std;
char * reverse (char *); //function prototype
int length(char *); //function prptotype

int main()
{
int i;
char *str = new char[6], *rev = new char[6];
cin >> str;
strcpy(rev,reverse(str));

cout <<"Original "<< str << " reverse " << rev << endl;
free(str);
free(rev);
return 0;
}

int length(char *s)
{
int i;
for (i=0; *(s+i)!='\0' ; ++i);
return i;
}

char *reverse(char *s)
{
char *t;
int i, n;
n=length(s);
t = new char[n];
for (i=0; i<n; ++i)
{
*(t+i)=*(s+n-1-i);
}
*(t+i)='\0';

return t;
}

/*based off of answer 8 i took this an intialized the
pointers so that it would run, and switched it over to the
C++ standard output commands. His algorithm was correct, he
just forgot to setup the memory*/

Given only putchar (no sprintf, itoa, etc.) write a routine putlong that prints out an unsigned long in decimal. [ I gave the obvious solution of taking % 10 and / 10, which gives us the decimal value in reverse order. This requires an array since we need to print it out in the correct order. The interviewer wasn't too pleased and asked me to give a solution which didn't need the array ].

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