Source schema has nodes First Name, Last Name and
destination schema has node Name. How we can get data at
destination so that we can have two instance of Name
(without using orchestration).
Answer Posted / navneet
Use the looping functoid to link FirstName and LastName to
Name. use this map as outbound map in send port binding.
| Is This Answer Correct ? | 2 Yes | 10 No |
Post New Answer View All Answers
What is custom pipeline?
Explain about biztalk server messaging services?
Explain about static, dynamic and direct binding?
In the dynamic send port actually we have to give the require destination details i.e, provided by client, but my question is how to get that particular address from where and where it is stored in biztalk?
what is the use of schema in biztalk and why we use schema?
I have a receive port and send port whose message types are different.When I receive a message in my receive port,my process starts.I will construct my out message and give this to my send port.I am configuring a send port group to the logical send port.TO the send port group I have added many send ports with filters.The message in the send ports are not getting filtered based on my filters?
Explain why messages are immutable inside biztalk?
What are the components of biztalk server architecture?
Is there any possibility in the biztalk FIFO(first-in-first-out) without use the orchestration? how to implement explain?
What is the latest version of biztalk server? : biztalk server
Define mapping?
what are un-typed messages?
Define bre?
What is biztalk server? : biztalk server
Did you deploy BizTalk more than one machine?