study the code:
#include<stdio.h>
void main()
{
const int a=100;
int *p;
p=&a;
(*p)++;
printf("a=%dn(*p)=%dn",a,*p);
}
What is printed?
A)100,101 B)100,100 C)101,101 D)None of the
above
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Answer Posted / abdur rab
the answer is c) 101, 101
a constant variable can be accessed using a pointer to
change the value because, during compilation the compiler
cannot see that the pointer is changing a contant read only
variable.
the same method can be applied over the private members in
a c++ class also.
| Is This Answer Correct ? | 3 Yes | 1 No |
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