Answer Posted / rahul khare

#include<stdio.h>
#include<conio.h>
void main()
{
int a[10],even=0,odd=0,i;
for(i=0;i<9;i++)
{
if(a[i]%2==0)
{
printf("%d\t",a[i]);
even++;
}
else
{
printf("%d\t",a[i]);
odd++;
}
}
printf("Total no of Even found is=%d",even);
printf("Total no of Odd found is=%d",odd);
getch();
}

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