int *p=20;
if u print like dis printf("%d",p);
o\p:- 20; how is it possible?
plz give me the explanation.
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Answer Posted / santhi perumal
We are assigning 20 to *p. Which means we are assigning the
address 20 to p. when you want to print the address of the
pointer variable we have to print just p not *p. if you want
to print the value stored in the particular address we need
to print like *p. in this case we are printing p so it will
give the address 20 to it.
| Is This Answer Correct ? | 31 Yes | 5 No |
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